提交 2d0ebc5d 编写于 作者: I Ilya Dryomov

libceph: rename MAX_OBJ_NAME_SIZE to CEPH_MAX_OID_NAME_LEN

In preparation for adding oid abstraction, rename MAX_OBJ_NAME_SIZE to
CEPH_MAX_OID_NAME_LEN.
Signed-off-by: NIlya Dryomov <ilya.dryomov@inktank.com>
Reviewed-by: NSage Weil <sage@inktank.com>
上级 e8221464
......@@ -1088,9 +1088,9 @@ static const char *rbd_segment_name(struct rbd_device *rbd_dev, u64 offset)
name_format = "%s.%012llx";
if (rbd_dev->image_format == 2)
name_format = "%s.%016llx";
ret = snprintf(name, MAX_OBJ_NAME_SIZE + 1, name_format,
ret = snprintf(name, CEPH_MAX_OID_NAME_LEN + 1, name_format,
rbd_dev->header.object_prefix, segment);
if (ret < 0 || ret > MAX_OBJ_NAME_SIZE) {
if (ret < 0 || ret > CEPH_MAX_OID_NAME_LEN) {
pr_err("error formatting segment name for #%llu (%d)\n",
segment, ret);
kfree(name);
......@@ -5350,7 +5350,7 @@ static int rbd_slab_init(void)
rbd_assert(!rbd_segment_name_cache);
rbd_segment_name_cache = kmem_cache_create("rbd_segment_name",
MAX_OBJ_NAME_SIZE + 1, 1, 0, NULL);
CEPH_MAX_OID_NAME_LEN + 1, 1, 0, NULL);
if (rbd_segment_name_cache)
return 0;
out_err:
......
......@@ -16,7 +16,7 @@
* Maximum object name size
* (must be at least as big as RBD_MAX_MD_NAME_LEN -- currently 100)
*/
#define MAX_OBJ_NAME_SIZE 100
#define CEPH_MAX_OID_NAME_LEN 100
struct ceph_msg;
struct ceph_snap_context;
......@@ -161,7 +161,7 @@ struct ceph_osd_request {
struct ceph_object_locator r_oloc;
char r_oid[MAX_OBJ_NAME_SIZE]; /* object name */
char r_oid[CEPH_MAX_OID_NAME_LEN]; /* object name */
int r_oid_len;
u64 r_snapid;
unsigned long r_stamp; /* send OR check time */
......
......@@ -338,7 +338,7 @@ struct ceph_osd_request *ceph_osdc_alloc_request(struct ceph_osd_client *osdc,
msg_size = 4 + 4 + 8 + 8 + 4+8;
msg_size += 2 + 4 + 8 + 4 + 4; /* oloc */
msg_size += 1 + 8 + 4 + 4; /* pg_t */
msg_size += 4 + MAX_OBJ_NAME_SIZE;
msg_size += 4 + CEPH_MAX_OID_NAME_LEN; /* oid */
msg_size += 2 + num_ops*sizeof(struct ceph_osd_op);
msg_size += 8; /* snapid */
msg_size += 8; /* snap_seq */
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册