###129. Sum Root to Leaf Numbers 题目: 难度: Medium 其实递归不难想到,不过我自己做错在细节方面 如果只有单支,每朝下走一层,代表的数字都增加10, 10* 原本的 + 新节点的数字,最终也是用这个来解 ``` class Solution(object): def sumNumbers(self, root): """ :type root: TreeNode :rtype: int """ return self.calSum(root,0) def calSum(self,root,curSum): if root == None: return 0 else: curSum = curSum * 10 + root.val if root.left == None and root.right == None: return curSum else: return self.calSum(root.left, curSum) + self.calSum(root.right, curSum) ```